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10x^2-60x+50=0
a = 10; b = -60; c = +50;
Δ = b2-4ac
Δ = -602-4·10·50
Δ = 1600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1600}=40$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-60)-40}{2*10}=\frac{20}{20} =1 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-60)+40}{2*10}=\frac{100}{20} =5 $
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